Can you read the part number on the tube? It is possibly a dual rectifier fed by a center-tapped transformer in a "full bridge" configuration. Is there a model number / manufacturer available for the chuck?
I am having trouble figuring out how you got 4.5mA from what you have said so far. 400V, 2000 Ohms, 900 Ohms. Where did the 400V number come from? Was your coil measurement done with the coil disconnected from the power supply?
One thing that concerns me is that the DC voltage you are talking about is very high and quite dangerous in the wrong circumstances. One bad wire nick inside the chuck could lead to high voltage on the case of the chuck. In any case, be very certain that all parts of the chuck and the power supply enclosure are well-grounded to the building's ground system. The chuck is very old so bad or near-failure point insulation is a pretty good bet.
If my guess about the circuit is correct, the 2000 Ohms is in series with 900 Ohm chuck coil (sort of), so that is 2900 Ohms. I = V/R. I = 400V / 2900 Ohms ~= 138 mA. From a glance at the assembly, it looks like the rectifier feeds the 2K resistor which feeds the capacitor. That would make for smooth DC output from the capacitor to the chuck. The math above is not exact because the 2K resistor current will be pulsing at 2X the line frequency and the 900 Ohm chuck current will be much more like "pure" DC.
This all can be easily replaced but it is important that the voltage rating of the chuck be known and that the insulation of the chuck be tested. Possibly ask around your area to see if there is someone that can "hipot" the coil for you to check the insulation between the coil and the case of the chuck.