- Joined
- Dec 26, 2015
- Messages
- 2,157
Excellent math:Okay, the size of a 215 insert is .250" inscribed circle. A triangle needs three sides being .433" long to contain a .25" circle.
Spilt in two so we have a hypotenuse of .433" and an opposite side of .2165". So that makes the adjacent side or the length of a 215 insert ~.375." long.
Somebody feel free to peer check me.