It would divide evenly, which seems like about all that matters. From there you can calculate out all the hole locations for the dividing plates easily. For low count dividing like hex, you would generally use the quick dividing plate, not the worm. So long as the pin and plate have a snug fit, any error would be minimized.
I could be missing something, as I don't do much dividing, but it doesn't seem unreasonable.
I could be missing something, as I don't do much dividing, but it doesn't seem unreasonable.