Assuming a taper length of 2", the major - minor diameter is 1.940" - 1.874" = .066". Half that is .033. That divided by 2" is .0165 which is the taper in in/in. This is also the sine of the half angle and the arcsin .0165 = .945º. If the taper length is 1.5", then the taper would be .022 "/" and the half angle would be 1.261º.
EDIT: Actually, it would be the tangent, not the sine. but the angle would still be .9453º for the 2" length and 1.2603º for the 15" length.
In SolidWorks, here is the solution.
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