How to mill a Rectangular Pocket with the Vertical Milling Machine

  • Thread starter Thread starter Tom Griffin
  • Start date Start date
WOW!!!
You were holding that in your hand !?!
Now I'm really impressed !!!!
You must have worked for Cirque Du Soleil !!!
 
I've thought about making video recordings of some of my work. I always thought I'd do a hand carry around to show the various important points, then mount on a tripod. Maybe if needed, stop the action and do another pan set, then back to action. Maybe I'll get a video camera. I use to have a couple, but never used them. Always missed everything else that I wasn't recording. Usually better stuff than I was getting.....in wildlife, anyway. I've done a couple of weddings that were ok.
 
Will work for free if you provide the airfare and board :)

I think the cheap flights from Perth to Detroit are around $2000. At that price you'd have to settle for a little extra water in the soup.

Tom
 
You know it is posts like these that make the heading redundant.........
This should be posted in the forum, This is how you...........

Cheers Phil
 
What do you mean Phil? It is posted in the How do I___ forum.

Tom
 
Tom,
Thanks, I learned a bunch from that video.:) I just have a question about calculating the desired movement of the cutter. I thought you determined the x movement from center as half the desired width of the hole minus the "diameter of the cutter". I would've thought it would be HALF the diameter of the cutter.
Did I misunderstand something? I'm completely new to this sort of thing. Just trying to learn.:thinking:

Tim,,,
 
That depends on your "origin" If you start off your x0,t0 at the center of the soon to be hole, then yes, your movements become half the hole plus half the cutter. BUT, if you start at a corner with your incremental moves from that as x0,y0, then it is hole dimensions less the full cutter. That's because you already have half the cutter behind the zero, or origin.
 
Thanks Tim,

To determine the cutter movement, take the full length or width of the pocket, subtract the diameter of the cutter and divide by two. I probably went too fast in the video when explaining that.

Tom
 
Thanks Tom, and Tony. I guess I overlooked the part about point of origin, or zero y and x point.
 
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