- Joined
- Sep 13, 2017
- Messages
- 8
The errors with alternate gear sets are small. For instance, the 37/47 set will give an error of .0032"/ft; the 44/56 set will give an error of .0327"/ft; and, the 63/80 set will give an error of .0002"/ft. If any set was to be problematic it would be the 44/56, however, you should not notice anything over the length of any normal nut, or any nut, even a long one, running on any length of shaft that you thread using these alternate gear sets.
For what it is worth.
This was posted earlier:
"Perfect ratio is 1.27:1 Take the other ratios and divide to get decimals 47/37= 1.27027027...
Error = 1.270707/1.27*100= 100.0213%"
If that is Correct, im still wondering what Math equation is used to obtain "the 37/47 set will give an error of .0032"/ft" ?
In the past, i believe i had read that the error for this (37/47)gearset was .0026"/ft.
In no way am i arguing the fact that the % of error is minimal for any of the gearsets, i only want to know exactly how it is calculated.....ie, how the % error equates to 0.000"/ft